Question

The first term of an A.P of $20$ terms is $2$ and its last term is $59$. Find its $6th$ term from the end $4$

Answer 1

Given (a) first term of AP = 2

n total terms = 20

$\left(a_n\right)$ least term = 59

We know $a_n=a+(n-1)d$

$59-2=19d$

$d=\frac{57}{19}=3$

$\therefore$ common difference of AP is .

For finding $6^{th}$ term from last.

out first term = 52 and last term = 2 & common difference = -3

now

$a_6=a+5d=59+5(-3)$

$a_6=59-15$

$[a_6=44]$

$\therefore 6^{th}$ term from last is 44.