the first term of an Ap is 5 common difference is 3 and the last is 80 find the number of terms

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Solution

$D e a r S t u d e n t L e t t h e l a s t t e r m o f A P b e a_{n} G i v e n f i r s t t e r m, a = 5 c o m m o n d i f f e r e n c e, d = 3 l a s t t e r m, a_{n} = 80 n o w a_{n} = a + (n - 1) d 80 = 5 + (n - 1) \times 3 80 = 5 + 3 n - 3 80 = 2 + 3 n 78 = 3 n n = 26 T h e r e f o r e n u m b e r o f t e r m s = 26 R e g a r d s$

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The first term of an AP is 5, last term is 45 and the sum is 400. Find the number of terms and the common difference.

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