The first term of an AP is unity and common difference is $5 .$ Which of the following will be a term of this AP.

4880

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7881

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5890

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7891

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Solution

The correct options are
B $7881$
D $7891$

$a = 1, d = 5 ∴ a_{n} = a + (n - 1) d$

$= 1 + (n - 1) 5 = 5 n - 4$
Consider option (A),

$4880 = 5 n - 4 5 n = 4884 n = (\frac{4884}{5}) = n o t a n i n t e g e r$
Consider option (B),

$7881 = 5 n - 4 5 n = 7885 n = (\frac{7885}{5}) = 1577 = i n t e g e r$
Consider option (C),

$5890 = 5 n - 4 5 n = 5894 n = (\frac{5894}{5}) = n o t a n i n t e g e r$
Consider option (D),

$7891 = 5 n - 4 5 n = 7895 n = (\frac{7895}{5}) = 1579 = i n t e g e r$

$* t w o o p t i o n s p o s s i b l e .$

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