the first term of an ap of 20 terms is 2 and its last term is 59 . find its 6th term from the end

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Solution

$H i, a = 2 a n d l = 59 a n d n = 20 s o l = a + (n - 1) d 59 = 2 + (20 - 1) \times d 19 d = 57 d = 3 S o 6 t h t e r m f r o m t h e e n d = 14 t h t e r m f r o m s t a r t = a + (n - 1) d = 2 + 13 \times 3 = 41 R e g a r d s$

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