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Question

The first term of an arithmetic sequence is 6 and common difference is 4. Then the algebraic expression for sum of the first 'n' terms its.


A

2n+4n2

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B

2+4n2

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C

2n2+4n

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D

2+4n

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Solution

The correct option is C

2n2+4n


Algebraic expression of the sequence is

=6+(n-1)4

=6+4n-4

=2+4n

Algebraic expression of sum of n terms whose nth term is 4n+2 is =4n(n+1)2+2n

=2n(n+1)+2n

=2n2+2n+2n=2n2+4n


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