The first term of an arithmetic sequence is 6 and common difference is 4. Then the algebraic expression for sum of the first 'n' terms its.
2n2+4n
Algebraic expression of the sequence is
=6+(n-1)4
=6+4n-4
=2+4n
Algebraic expression of sum of n terms whose nth term is 4n+2 is =4n(n+1)2+2n
=2n(n+1)+2n
=2n2+2n+2n=2n2+4n