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Question

The first three terms in the expansion of (1+a)n are t1=1,t2=−18,t3=144.

Use the general term to determine a and n.


A
a=3,n=9
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B
a=2,n=9
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C
a=3,n=8
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D
a=2,n=8
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Solution

The correct option is B a=2,n=9
As we can see from option that n is positive so we proceed with the expansion
T1 = nC0 =1
T2 = nC1a =n.a=18 ....(1)
T3 = nC2a2 = (n)(n1)2.a2 =144 ....(2)
(na)(naa).=288
Putting the value of na from (1), we get
(18)(18a) =288
18a =16
a=2
So, a=2
Substitute this value of a in equation (1), we get
na=18
n(2)=18
n=9
Thus value of a and n are 2 and 9.

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