The first two terms of an AP are −5 and 6. Its 21st term is
(a) 115
(b) −115
(c) −215
(d) 215

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Solution

(d) 215
Here, T₁ or a = -5 and T₂ = 6
Then, d = T₂ - T₁= 6 - (-5) = 11
Now, T₂₁ = a + 20d = -5 + 20 ⨯ 11 = 215
Hence, the 21^st term of the given AP is 215.

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