Question

Question 120.
The fish caught by Neetu was of weight $3\frac{3}{4}$ kg and the fish caught by Narendra was of weight $2\frac{1}{2}$ kg. How much more did Neetu's fish weight than that of Narendra?

Answer 1

Given that

The weight of fish caught by Neetu = $3\frac{3}{4}$ kg
The weight of fish caught by Narendra = $2\frac{1}{2}$ kg
Difference between the weight of Neetu's fish and Narendra's fish = $3\frac{3}{4}-2\frac{1}{2}$

We can express a mixed fraction as an improper fraction as $\frac{(\text{Whole}\times \text{Denominator})\text{+ Numerator}}{\text{Denominator}}$.

Difference between the weight of Neetu's fish and Narendra's fish = $3\frac{3}{4}-2\frac{1}{2}=\frac{3\times 4+3}{4}-\frac{2\times 2+1}{2}=\frac{15}{4}-\frac{5}{2}$

Now, the LCM of the denominator of the fractions $\frac{15}{4}$ and $\frac{5}{2}$ i.e. the LCM of 4 and 2 is 4.

$\therefore$ Difference between the weight of Neetu's fish and Narendra's fish =$\frac{15\times 1}{4\times 1}-\frac{5\times 2}{2\times 2}=\frac{15}{4}-\frac{10}{4}$
Difference between the weight of Neetu's fish and Narendra's fish =$\frac{15}{4}-\frac{10}{4}=\frac{15-10}{4}=\frac{5}{4}$

We can express an improper fraction as a mixed fraction by dividing the numerator by denominator to obtain the quotient and the remainder.

Then the mixed fraction will be written as $\text{Quotient}\frac{\text{Remainder}}{\text{Divisor}}$.

$\left[\begin{array}{c}\because 4\left)5\right(1\\ \frac{4}{1}\end{array}\right]$

Difference between the weight of Neetu's fish and Narendra's fish =$1\frac{1}{4}kg$
So, Neetu's fish weighed $1\frac{1}{4}$ kg more than that of Narendra.