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Question

The fishing pole in figure makes an angle of 200 with the horizontal. What is the torque exerted by the fish about an axis perpendicular to the page and passing through the angler’s hand if the fish pulls on the fishing line with a force F=100N ­ at an angle 330 below the horizontal? The force is applied at a point 200m from the angler's hands.

A
120 Nm (anticlockwise)
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B
160 Nm (anticlockwise)
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C
160 Nm (clockwise)
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D
120 Nm (clockwise)
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Solution

The correct option is C 160 Nm (clockwise)

Resolve the 100 N force into components
perpendicular to and parallel to the rod.
FII=100cos53=60N
F=100sin53=80N
The torque due to FII is zero since its line of action passes through the pivot point.

The torque due to F is,
r=80×2=160Nm (Clockwise)
Final Answer: b

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