Question

The floor of a building consists of $3000$ tiles which are rhombus shaped and each of its diagonals are $45cm$ and $30cm$ in length. Find the total cost of polishing the floor, if the cost per $m^2$ is $Rs.4$.

Answer 1

Number of rhombus shaped tiles $=3000$

Diagonals of each tile $45cm$ and $30cm$

$\therefore Areaofonetile=\frac{d_1\times d_2}{2}=\frac{45\times 30}{2}=675c{m}^2\therefore Areaof3000tiles=675\times 3000c{m}^2=2025000c{m}^2=\frac{2025000}{100\times 100}=202.5m^{2}Rateofpolishingthetiles=Rs.4per{m}^2\therefore Totalcost=202.5\times 4=Rs.810$