Question

The floor of a building consists of 3000 tiles which are rhombus shaped and each of its diagonals are 45 cm and 30 cm in length. Find the total cost of polishing the floor, if the cost per $m^2$ is 4.

Answer 1

Number of rhombus shaped tiles = 3000

Diagonals of each tile = 45 cm and 30 cm

$\therefore \text{Area of one tile}=\frac{1}{2}\times d_1\times d_2=\frac{1}{2}\times 45\times 30=675{\text{cm}}^2$

$\text{Area of}3000\text{tiles}=675\times 3000{\text{cm}}^2=2025000{\text{cm}}^2$

$=\frac{2025000}{100\times 100}=202.5{\text{m}}^2$

$\text{Rate of polishing the tiles}=Rs.4{\text{per m}}^2$

$\therefore \text{Total cost}=202.5\times 4$

$=Rs.810$