Question

The floor of a building consists of 3000 tiles which are rhombus shaped and each of its diagonals are 45 cm and 30 cm in length. Find the total cost of polishing the floor, if the cost per $m^2$ is Rs. 4.

Answer 1

Total number of tiles used = 3000

Since tile is in the shape of rhombus and diagonals are 45 cm and 30 cm, thus,

$d_1=30cm$ and $d_2=45cm$

Area of one tile = Area of rhombus

$=\frac{1}{2}\times d_1\times d_2$

$=\frac{1}{2}\times 30\times 45=675c{m}^2$

Area of 3000 tiles = $3000\times 675=2025000c{m}^2$

$=\frac{2025000}{10000}{m}^2=202.5m^2$

Cost of polishing $1m^2=4$

Cost of publishing $202.5m^2=4\times 202.5=Rs.810$