Question

The floor of a building consists of 3000 tiles which are rhombus shaped and each of its diagonals are 45 cm and 30 cm in length. Find the total cost of polishing the floor, if the cost per $m^2$ is Rs. 4.

Answer 1

Length of one diagonal, $d_1$ = 45 cm and $d_2$ = 30 cm

$\because$ Area of one tile $=\left(\frac{1}{2}\right)d_1{d}_2$

$=\left(\frac{1}{2}\right)\times 45\times 30=675c{m}^2$

Area of one tile is 675 cm${}^2$

Area of 3000 tiles is

$=675\times 3000=2025000c{m}^2$

$=\frac{2025000}{10000}$

$=202.50m^2[\because 1m^2=10000c{m}^2]$

$\because$ Cost of polishing the floor per sq. meter = Rs 4

Cost of polishing the floor per 202.50 sq. meter = 4 $\times$ 202.50 = Rs. 810

Hence the total cost of polishing the floor is Rs. 810.