Question

The floor of a building consists of 3000 tiles which are rhombus shaped. The diagonals of each of the tiles are 45 cm and 30 cm. Find the total cost of polishing the floor, if cost per $m^2$ is Rs 2.50.

Answer 1

Cost $=$ Area $\times$ Rate

And Area of Rhombus $=\frac{1}{2}{d}_1{d}_2$

Cost $=(\frac{1}{2}45\times 30)c{m}^2\times 3000\times \frac{2.5Rs}{m^2}$

$=\frac{45\times 15}{\left(100\right)\left(100\right)}{m}^2.3000\times 2.5\frac{Rs}{m^2}$

$=\frac{45\times 45}{10}\times 2.5Rs$

$=506.25Rs$