The floor of a rectangular hall has a perimeter $250 m$ . If the cost of painting the four walls at the rate of $10 p e r m^{2}$ is $15000$ , find the height of the hall.

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Solution

Given perimeter of the floor of rectangular hall $= 250$ m
i.e., $2 (l + b) = 250$
$l + b = 125$

Area of four walls $= 2 h (l + b)$
$= 2 h (125)$
$= 250 h$

Given cost of painting at rate $10$ per $m^{2} = 15000$

i.e., $10 (L S A) = 15000$

$10 (250) h = 15000$

$h = 6$ m.

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Similar questions

Q. The floor of a rectangular hall has a perimeter 250m. If the cost of panting the four walls at the rate of Rs.10 per

m^{2}

is Rs.15000, find the height of the hall.

Q. The floor of a rectangular hall has a perimeter

250 m

. If the cost of painting the four walls at the rate of Rs.

10

per

m^{2}

is Rs.

15000

, find the height (in cm) of the hall.
(Hint: Area of the four walls = Lateral surface area)

The floor of a rectangular hall has a perimeter $250 m$ . If the cost of painting the four walls at the rate of Rs $10$ per $m^{2}$ is $15000$ , find the height of the hall (in meters).

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The floor of a rectangular hall has a perimeter 250m. If the cost of painting the four walls at the rate of 10perm2 is 15000, find the height of the hall.

Given perimeter of the floor of rectangular hall=250mi.e., 2(l+b)=250l+b=125Area of four walls=2h(l+b)=2h(125)=250hGiven cost of painting at rate 10 per m2=15000i.e., 10(LSA)=1500010(250)h=15000h=6m.

The floor of a rectangular hall has a perimeter $250 m$ . If the cost of painting the four walls at the rate of $10 p e r m^{2}$ is $15000$ , find the height of the hall.

Given perimeter of the floor of rectangular hall $= 250$ m
i.e., $2 (l + b) = 250$
$l + b = 125$

Area of four walls $= 2 h (l + b)$
$= 2 h (125)$
$= 250 h$

Given cost of painting at rate $10$ per $m^{2} = 15000$

i.e., $10 (L S A) = 15000$

$10 (250) h = 15000$

$h = 6$ m.