The floor of a rectangular hall has a perimeter 250 m. If the cost of painting the four walls at the rate of Rs.10 per m $^{2}$ is Rs.15000, find the height of the hall.

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Solution

Let length, breadth, and height of the rectangular hall be $l, b$ , and $h$ respectively.
Area of four walls $= 2 l h + 2 b h$
$= 2 (l + b) h$
Perimeter of the floor of hall $= 2 (l + b)$
$= 250$ m
Area of four walls $= 2 (l + b) h = 250 h$ m $^{2}$
Cost of painting per square meter area = Rs.10
Cost of painting $250 h$ square meter area = Rs $250 h \times 10$ = Rs. $2500 h$
However, it is given that the cost of painting the walls is Rs. $15000.$
$15000 = 2500 h$
or $h = 6$
Therefore, the height of the hall is $6$ m.

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The floor of a rectangular hall has a perimeter 250 m. If the cost of painting the four walls at the rate of Rs.10 per m2 is Rs.15000, find the height of the hall.

The floor of a rectangular hall has a perimeter 250 m. If the cost of painting the four walls at the rate of Rs.10 per m $^{2}$ is Rs.15000, find the height of the hall.