Question

The floor of building consist of 3000 tiles which are rhombus shaped and each of its diagonals are 45$cm$ and 30$cm$ in length.Find the total cost of flooring if each tile costs per $m^2$ is $Rs2.50$

Answer 1

The diagonals of rhombus are $45cm$ and $30cm$

The area of one tile is $\frac{1}{2}\times 45\times 1545\times 15=675c{m}^2$

Area of $3000$ such tiles is $3000\times 675=2025000c{m}^2$

$1m^2=10000c{m}^{2}202.5m^2=2025000c{m}^2$

Cost of $1m^2$ is $Rs.2.50$

Cost of $202.5m^2$ is $Rs.2.5\times 202.5=506.25Rs.$