Question

The flow net constructed for a dam is shown in the figure below. Taking coefficient of permeability as $3.8\times {10}^{-6}m/s$, the quantity of flow $\left(inc{m}^3/sec\right)$ under the dam per m is

• A. 7.182

Answer 1

The correct option is A 7.182

$Q=KH\frac{N_f}{N_d}$

$N_d=10$

$N_f=3$

H = 6.3 m

$K=3.8\times {10}^{-6}m/s$

$Q=3.8\times {10}^{-6}\frac{m}{s}\times 6.3m\times \frac{3}{10}$

$=7.182\times {10}^{-6}\frac{m^3/s}{m}$

$=7.182\times {10}^{-6}\times {10}^6\frac{c{m}^3/s}{m}$

$Q=7.182\frac{c{m}^3/s}{m}$