The fluoride of $x e n o n$ with zero dipole moment is :

X e F_{6}

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X e O_{3}

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X e F_{4}

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X e F_{2}

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Solution

The correct options are
C $X e F_{2}$
D $X e F_{4}$
$X e F_{4}$ is square planar and $X e F_{2}$ is linear in shape. The molecules are symmetrical and so the vector sum of the individual dipole moment is zero.

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Similar questions

How are xenon fluorides $X e F_{2}, X e F_{4}$ and $X e F_{6}$ obtained?

Q. The fluoride of xenon with zero dipole moment is:

Q. Oxidising power of xenon fluorides increases in the order:

X e F_{6} > X e F_{4} > X e F_{2}

If true enter 1, else enter 0.

Xenon forms three binary fluorides $X e F_{2}, X e F_{4}$ and $X e F_{6}$ . All the three fluorides are colourless crystalline solids sublimating at 295K. They are powerful fluorinating agents and they are readily hydrolysed by water.
The shape of $X e O_{3}$ is:

Q. Which of the following fluoride of xenon has zero dipole moment?

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The fluoride of xenon with zero dipole moment is :

The correct options are C XeF2 D XeF4XeF4 is square planar and XeF2 is linear in shape. The molecules are symmetrical and so the vector sum of the individual dipole moment is zero.

The fluoride of $x e n o n$ with zero dipole moment is :

The correct options are
C $X e F_{2}$
D $X e F_{4}$
$X e F_{4}$ is square planar and $X e F_{2}$ is linear in shape. The molecules are symmetrical and so the vector sum of the individual dipole moment is zero.