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Question

The fluoride of $$xenon$$ with zero dipole moment is :


A
XeF6
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B
XeO3
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C
XeF4
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D
XeF2
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Solution

The correct options are
C $$\mathrm{X}\mathrm{e}\mathrm{F}_{2}$$
D $$\mathrm{X}\mathrm{e}\mathrm{F}_{4}$$
$$XeF_{4}$$ is square planar and $$XeF_2$$ is linear in shape. The molecules are symmetrical and so the vector sum of the individual dipole moment is zero.
70400_26586_ans.jpg

Chemistry

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