Question

# The fluoride of $$xenon$$ with zero dipole moment is :

A
XeF6
B
XeO3
C
XeF4
D
XeF2

Solution

## The correct options are C $$\mathrm{X}\mathrm{e}\mathrm{F}_{2}$$ D $$\mathrm{X}\mathrm{e}\mathrm{F}_{4}$$$$XeF_{4}$$ is square planar and $$XeF_2$$ is linear in shape. The molecules are symmetrical and so the vector sum of the individual dipole moment is zero.Chemistry

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