The flux entering and leaving a closed surface are 5×10^5 and 4×10^5 in si unit the charge inside the surface is

-8.85×10^-7 c

8.85×10^-7

8.85×10^-7

-6.85×10^7

6.85×10^-7

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Solution

The charge inside the surface
qenc=(ϕ2−ϕ1)∈0
ϕ1=5×10^5
ϕ2=4×10^5
= (410^5-510^5)8.854210^-12 [ε_o = 8.8542×10^-12 Fm^-1]
= -10^58.854210^-12
= -8.8510^-7

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The flux entering and leaving a closed surface are 5×10^5 and 4×10^5 in si unit the charge inside the surface is -8.85×10^-7 c 8.85×10^-7 8.85×10^-7 -6.85×10^7 6.85×10^-7

The charge inside the surface qenc=(ϕ2−ϕ1)∈0 ϕ1=5×10^5 ϕ2=4×10^5 = (4*10^5-5*10^5)8.8542*10^-12 [εo = 8.8542×10-12 Fm-1] = -10^5*8.8542*10^-12 = -8.85*10^-7

The flux entering and leaving a closed surface are 5×10^5 and 4×10^5 in si unit the charge inside the surface is

-8.85×10^-7 c

8.85×10^-7

8.85×10^-7

-6.85×10^7

6.85×10^-7

The charge inside the surface
qenc=(ϕ2−ϕ1)∈0
ϕ1=5×10^5
ϕ2=4×10^5
= (410^5-510^5)8.854210^-12 [ε_o = 8.8542×10^-12 Fm^-1]
= -10^58.854210^-12
= -8.8510^-7