Question

The flux linked with a circuit is given by $\varphi ={(t-2)}^2.$ The graph between induced emf (y-axis) and time axis (x-axis) is

• A. Straight line through origin
• B. Straight line with negative intercept
• C. Straight line with positive intercept
• D. Parabola

Answer 1

The correct option is C Straight line with positive intercept

Using the Faraday's law,

$\varphi ={(t-2)}^2$

or, $\frac{d\varphi }{dt}=2(t-2)$

$y=2(t-2)$

or, $y=2t-4$. This is the formula of the straight line with $(+Ve)$ intercept because $y=mx+C$ will be $(-Ve)$ intercept when general formula of straight line $y=mx-C$

$\tan \theta$ then the picture draws.