Question

The flux of electric field E=$200$ iNC through a cube of side $10$ cm, oreinted so that its faces are parallel to the co-ordinate axes is

Answer 1

Given, electric fleld $E=200NC$ and each sides of cube is 0.1 m

Area of a side is $\Delta S={\left(0.1\right)}^2{m}^2$

Let two opposite surface be $\Delta S_1$ and $\Delta S_2$

Magnetic flux, $\varphi =E.\Delta \overrightarrow{S_1}+E.\Delta \overrightarrow{S_2}$

The angle between E and $\Delta S_1$ is zero and angle between

$\Delta S_2$ is 180 degree

$\therefore \varphi =E\Delta S_{1}cos0+E.\Delta cos\left({180}^0\right)$

$=E\times 0.01\times 1+E\times 0.01\times (-1)$

= 0