The focal distance of a point on the parabola y2=16x whose ordinate is twice the abscissa, is
A
6
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B
8
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C
10
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D
12
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Solution
The correct option is B 8 Let point be (h, k).But 2h = k, then k2=16h ⇒4h2=16h⇒h=0,h=4⇒k=0,k=8 ∴Points are (0,0), (4,8). Focal distance of any point (x,y) on the parabola y2=4ax is given by x+a. Hence focal distances are 0 + a = 4, and 4 + 4 = 8