The focal distance of the point (9, 6) on the parabola $y^{2} = 4 x$ is

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Solution

The correct option is C 10
$y^{2} = 4 x \Rightarrow 4 a = 4 \Rightarrow a = 1 F o c u s = S = (a, 0) = (1, 0), P (9, 6) ∴ F o c a l d i s t a n c e = S P = \sqrt{(9 - 1)^{2} + (6 - 0)^{2}} = \sqrt{64 + 36} = 10$

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