The focal length of a convex lens is 10 cm and its refractive index is 1.5 .If the radius of curvature of one surface is 7.5 cm ,the radius of curvature of the second surface will be

7.5 cm

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-15.0 cm

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75 cm

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5.0 cm

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Solution

The correct option is C -15.0 cm
As we know,
$\frac{1}{f} = (μ - 1) (\frac{1}{R_{1}} - \frac{1}{R_{2}})$
$\Rightarrow \frac{1}{+ 10} = (1.5 - 1) (\frac{1}{+ 7.5} - \frac{1}{R_{2}}) \Rightarrow R_{2} = - 15 c m$

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