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Power and Thin Lenses in Contact

The focal len...

Question

The focal length of the combination of two convex lens in contact is $f$ and if they are separated by a distance, then focal length of the combination is $f_{1}$ . The correct statement is

f > f_{1}

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f = f_{1}

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f < f_{1}

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f f_{1} = 1

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Solution

The correct option is C $f < f_{1}$
$f$ will be less than $f_{1}$

$E x p l a n a t i o n$

$\frac{1}{f} = \frac{1}{F_{1}} + \frac{1}{F_{2}}$

$\frac{1}{f_{1}} = \frac{1}{F_{1}} + \frac{1}{F_{2}} - \frac{d}{F_{1} F_{2}}$
where $d$ is the distance between lenses.

Option C is correct.

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Similar questions

If two thin lenses of focal length f₁ and f₂ are held in contact then the focal length of the combination will be

^{'} f^{'}

^{'} f^{'}

\frac{1}{F} = \frac{1}{f_{1}} + \frac{1}{f_{2}} - \frac{d}{f_{1} f_{2}}

F =

f_{1}

f_{2}

^{'} d^{'}

f_{1}

f_{2}

\frac{1}{f} = \frac{1}{f_{1}} + \frac{1}{f_{2}}

\frac{1}{F} = \frac{1}{F_{1}} + \frac{1}{F_{2}}

f_{1}

f_{2}

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