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Angular Magnification in Telescope

The focal len...

Question

The focal length of the objective of a telescope is 60 cm. To obtain a magnification of 20, the focal length of the eye piece should be

A

2 cm

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B

3 cm

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C

4 cm

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D

5 cm

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Solution

The correct option is A 3 cm
In normal adjustment:
$M = \frac{f_{0}}{f_{e}} = 20$

$\Rightarrow f_{e} = \frac{f_{0}}{20} = \frac{60}{20} = 3 c m$

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