The focal lengths of an objective lens and eyepiece are $192 c m$ and $8 c m$ respectively in a small telescope. Calculate its magnifying power and the separation between the two lenses.

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Solution

Focal length of the objective lense $(f_{0}) = 192 c m$
Focal length of the eyepiece $(f_{e}) = 8 c m$
The magnifying power of the telescope $(m) = f_{0} / f_{e} = 192 / 8 = 24 c m$ ,
The separation between the objective lens and the eyepiece is $= 192 + 8 = 200 c m$

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The focal lengths of an objective lens and eyepiece are 192 cm and 8 cm respectively in a small telescope. Calculate its magnifying power and the separation between the two lenses.

Focal length of the objective lense(f0)=192cm Focal length of the eyepiece (fe)=8cm The magnifying power of the telescope (m)=f0/fe=192/8=24cm, The separation between the objective lens and the eyepiece is =192+8=200cm

The focal lengths of an objective lens and eyepiece are $192 c m$ and $8 c m$ respectively in a small telescope. Calculate its magnifying power and the separation between the two lenses.

Focal length of the objective lense $(f_{0}) = 192 c m$
Focal length of the eyepiece $(f_{e}) = 8 c m$
The magnifying power of the telescope $(m) = f_{0} / f_{e} = 192 / 8 = 24 c m$ ,
The separation between the objective lens and the eyepiece is $= 192 + 8 = 200 c m$