The focus and directrix of a parabola are (1,2) and 2x-3y+1=0. Then the equation of the tangent at vertex is
4x-6y+5=0
4x-6y+9=0
4x-6y+11=0
4x-6y+7=0
S=(2,1)Directrix 2x−3y+1=0 Eqn of L.R is 2(x−1)−3(y−2)=0 ∴ Eqn of tgt at vertex is ⇒2x−3y+4=0 2x−3y+1+42=0 ⇒4x−6y+5=0
The diameters of a circle are along 2x+y-7 and x+3y-11=0 Then the equation of this circle,which also passes through (5,7) is
Tangents are drawn from the point P(1, 8) to the circle x2+y2−6x−4y−11=0 touch the circle at the point A and B, then equation of the circumcircle of the triangle PAB is