The focus and vertex of a parabola are (4,5) and (3,6). The equation of axis is

2x-y+3=0

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2x-y=0

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2x+y-13=0

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x+y-9=0

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Solution

The correct option is D
x+y-9=0

$S = (4, 5)$ Eqn of axis $\frac{y - 5}{1} = \frac{x - 4}{- 1}$
$A = (3, 6) \Rightarrow - y + 5 = x - 4 \Rightarrow x + y - 9 = 0$

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