The focus of parabola $x^{2} = - 16 y$ is

(4, 0)

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(0, 4)

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(-4, 0)

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(0, -4)

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Solution

The correct option is D (0, -4)
The given parabola is of the form $x^{2} = 4 a y$ .
Focus of this parabola is (0,a)
Here a = -4
=> focus is (0,-4)

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