The focus of the parabola $(x - 2)^{2} = 16 (y - 4)$ is

(2, 4)

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(4, 2)

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(2, 8)

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(4, 6)

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Solution

The correct option is C $(2, 8)$
$(x - 2)^{2} = 16 (y - 4) .$
$h = 2; k = 4 .$
$4 P = 16 \Rightarrow P = 4.$
focus $(2, 4 + 4) = (2, 8)$

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Similar questions

x^{2} = - 16 y

List-l	List - II
A. Length of the latusrectum of the parabola $3 y^{2} = - 4 x$	1. $(5, 2)$
B.Equation of the parabola whose focus $($ 0,4 $)$ and directrix $x + 4 = 0$ is	2. $\frac{- 4}{3}$
C. The focus of the parabola $(y - 2)^{2} = 8 (x - 3)$ is	3. $\frac{4}{3}$
D. Equation of the parabola whose vertex $(- 1, - 2)$ latusrectum 4 and axis is parallel to y-axis	4. $(x + 1)^{2} = 4 (y + 2)$
	5. $x^{2} = 16 y$