The focus of the parabola x2−2x=2y is
(32,−12)
(1,−12)
1,0
0,1
The parabola is x2−2x=2y
Or x2−2x+1=2y+1⇒(x−1)2=2(y+12)Here 4a=2⇒a=12Now focus is (x−1=0, y+12=12)i.e.,(1,0)