Question

The following are two reaction schemes involving Mg.

Scheme-I : Mg $\stackrel{air\Delta }{\to }$ colourless solid A $\stackrel{HCl}{\to }$ colourless soltuion B $\stackrel{N{a}_{2}C{O}_3}{\to }$ white ppt C $\stackrel{\Delta }{\to }$D colourless gas E $\stackrel{Ca(OH{)}_2}{\to }$ white ppt F

Scheme-II : Mg $\stackrel{dil.H_{2}S{O}_4}{\to }$ colourless solution G $\stackrel{NaOH}{\to }$ white ppt H $\stackrel{HN{O}_3}{\to }$ colourless solution $\stackrel{evaporate}{\to }$ I $\stackrel{\Delta }{\to }$ J gas + $O_2+D$

Find I.

• A. $Mg\left(N{O}_2\right)$
• B. $Mg(N{O}_2{)}_2$
• C. $Mg(N{O}_3{)}_2$
• D. $Mg\left(N{O}_3\right)$

Answer 1

The correct option is C $Mg(N{O}_3{)}_2$

Scheme-I : Mg $\stackrel{air\Delta }{\to }$ colourless solid MgO $\stackrel{HCl}{\to }$ colourless soltuion $MgC{l}_2\stackrel{N{a}_{2}C{O}_3}{\to }MgC{O}_3$ white ppt $\stackrel{\Delta }{\to }$ $MgO$ + colourless gas $C{O}_2$ $\stackrel{Ca(OH{)}_2}{\to }$ white ppt $CaC{O}_3$

Scheme-II : $Mg$ $\stackrel{dil.H_{2}S{O}_4}{\to }$ colourless solution $MgS{O}_4\stackrel{NaOH}{\to }$ white ppt $Mg(OH{)}_2\stackrel{HN{O}_3}{\to }$ colourless solution $\stackrel{evaporate}{\to }$ $Mg(N{O}_3{)}_2\stackrel{\Delta }{\to }N{O}_2$ gas + $O_2+MgO$

Thus, I is $Mg(N{O}_3{)}_2$.