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Byju's Answer
Standard XII
Chemistry
Faraday's First Law
The following...
Question
The following cell has a potential of 0.55 V at 25
o
C.
P
t
(
s
)
|
H
2
(
1
a
t
m
)
|
H
+
(
?
M
)
|
|
C
l
−
(
1
M
)
|
H
g
2
C
l
2
(
s
)
|
H
g
(
l
)
What is the pH of the solution in the anodic chamber?
E
C
l
−
/
H
g
2
C
l
2
/
H
g
=
0.28
V
A
4.57
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B
14.07
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C
9.15
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D
7.15
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Solution
The correct option is
A
4.57
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0
Similar questions
Q.
The cell
P
t
|
H
2
(
g
,
0.1
b
a
r
)
|
H
+
(
a
q
)
,
p
H
=
X
|
|
C
l
−
(
a
q
,
1
M
)
|
H
g
2
C
l
2
|
H
g
|
P
t
,
has e.m.f. of
0.5755
V
at
25
∘
C
. The SOP of calomel electrode is
−
0.28
V
, then
p
H
of the solution will be:
Q.
For the following cell having a hydrogen electrode and a normal calomel electrode, the electromotive force (EMF) is
0.634
V at
298
K.
P
t
[
H
2
(
1
a
t
m
)
|
H
+
(
p
H
=
x
)
∥
K
C
l
(
1
N
)
|
H
g
2
C
l
2
(
s
)
|
H
g
(
l
)
If
E
o
of
C
l
−
|
H
g
2
C
l
2
|
H
g
is
0.28
V, then select the incorrect statements.
Q.
Construct galvanic cells from the following pairs of half cells and calculate their emf at
25
o
C
.
C
d
2
+
(
a
q
,
1
M
)
∣
C
d
(
s
)
;
E
0
C
d
2
+
/
C
d
=
−
0.40
V
H
g
2
C
l
2
(
s
)
∣
H
g
(
l
)
∣
C
l
−
(
a
q
,
0.1
M
)
;
E
0
C
l
−
/
H
g
2
C
l
2
/
H
g
=
0.28
V
Q.
The cell Pt,
H
2
(
1
a
t
m
)
|
H
+
(
p
H
=
x
)
|
|
Normal calomel Electrode has an EMF of 0.67 V at
25
∘
C
. The pH of the solution is:
The oxidation potential of the calomel electrode on hydrogen scale is
−
0.28
V
.
(write the value to the nearest integer)
Q.
The EMF of the cell
p
t
,
H
2
(
1
a
t
m
)
|
H
⊕
(
c
)
|
|
K
C
l
(
s
a
t
u
r
a
t
e
d
)
|
H
g
2
C
l
2
|
H
g
(
s
)
is
0.36
V. The RHE is know as calomel electrode and its standard electrode potential is +
0.242
V. Find the
H
⊕
ions concentration in LHE and hence find the pH of LHE.
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