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Question

The following compound can be called as

A
D-(+)-glucose
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B
D-(-)-glucose
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C
L-(-)-glucose
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D
L-(+)-glucose
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Solution

The correct option is A D-(+)-glucose
Steps to Find Out ​D & L Configuration
1. Write the molecule in such ​a way that most oxidised​ carbon (-CHO) is at top.
2. Check lowest chiral carbon.
3. Observe the position of -OH attached to that carbon​.
(a) if -OH on the right side, assigned as 'D' ​configuration.
(b) if -OH on the left side, assigned as 'L' ​configuration.

Optical Behaviour of Glucose ​
(+) or (d) represents Dextrorotatory
(-) or (l) represents Laevorotatory​
NOTE: D and L are relative configuration and have no relation with d/(+) and l/(-)​.

'D' before the name of glucose represents the configuration whereas '(+)' represents dextrorotatory nature of the molecule. When the -OH group lies on right hand side in the structure it is said to have D configuration. In (+) glucose, -OH on the lowest asymmetric carbon is on the right side so (+) glucose is assigned to D-configuration. thus glucose is correctly named as D-(+)-glucose. Hence (a) is the correct option.

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