wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The following concentration were obtained for the formation of NH3 form N2 and H2 at equilibrium for the reaction N2(g)+3H2(g)2NH3(g)

[N2]=1.5×102M
[H2]=3.0×102M
[NH3]=1.2×102M

Calculate equilibrium constant.

A
310.0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
536.0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
556.0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
356.0
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D 356.0
The following reaction is taking place,
N2(g)+3H2(g)2NH3(g)

Given:
[N2]=1.5×102M
[H2]=3.0×102M
[NH3]=1.2×102M

Kc can be written as:
Kc=[NH3]2[N2][H2]3

Kc=(1.2×102)(1.5×102)(3.0×102)

Kc=355.5

flag
Suggest Corrections
thumbs-up
1
Join BYJU'S Learning Program
Join BYJU'S Learning Program
CrossIcon