The following data, $Δ H = 9.2 k J m o l^{- 1}$ , $Δ S = 0.008 k J K^{- 1} m o l^{- 1}$ is known about the melting of a compound $A B$ . Its melting point is

736 K

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1050 K

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1150 K

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1250 K

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Solution

The correct option is C $1150 K$
For the melting point,

$Δ G = 0$

$Δ H = T Δ S$

$9.2 = T Δ S$

$9.2 = T \times 0.008$

$100 \times \frac{92}{8} = T$

$100 \times 11.5 = T$

$T = 1150 K$

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