The following data gives the marks obtained by students in an exam-WlineBelow - 10 - 5 WlhlineBelow 20 - 10 Wlhline Below 30 - 23 Whline Below 40 - 31 WhlineBelow 50 - 45 wlhlineBelow 60 - 49 Wlhline array iConvert the cumulative distribution to a regular distribution-iiCalculate the mode- -3 MARKS-

Table: 1 Mark Application: 2 Marks [ Class Interval amp;Frequency; 0 10 amp; 5; 10 20 amp; 5; 20 30 amp; 13 ...

You visited us 3 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard X

Mathematics

Grouped Frequency Table

The following...

Question

The following data gives the marks obtained by students in an exam.

$\begin{matrix} Class interval & Frequency B e l o w 10 & 5 B e l o w 20 & 10 B e l o w 30 & 23 B e l o w 40 & 31 B e l o w 50 & 45 B e l o w 60 & 49 \end{matrix}$

(i)Convert the cumulative distribution to a regular distribution.

(ii)Calculate the mode. [3 MARKS]

Open in App

Solution

Table: 1 Mark
Application: 2 Marks

$\begin{matrix} Class Interval & Frequency 0 - 10 & 5 10 - 20 & 5 20 - 30 & 13 30 - 40 & 8 40 - 50 & 14 50 - 60 & 4 \end{matrix}$

Mode
$= I + (\frac{f_{1} - f_{0}}{2 f_{1} - f_{0} - f_{2}}) \times h$

$= 20 + \frac{13 - 5}{26 - 5 - 8} \times 10$

$= 26.15$

Suggest Corrections

Similar questions

The following table gives the marks obtained by the students of a class in an exam out of 50.

$\begin{matrix} M a r k s & N o . o f S t u d e n t s B e l o w 10 & 5 B e l o w 20 & 10 B e l o w 30 & 23 B e l o w 40 & 31 B e l o w 50 & 40 \end{matrix}$

(i) Convert the cumulative frequency distribution into a regular frequency distribution.

(ii) Find the mean.

The following data gives the marks obtained by students in an exam.

$\begin{matrix} Class interval & Frequency B e l o w 10 & 5 B e l o w 20 & 10 B e l o w 30 & 23 B e l o w 40 & 31 B e l o w 50 & 45 B e l o w 60 & 49 \end{matrix}$

(i)Convert the cumulative distribution to a regular distribution.

(ii)Calculate the mode. [3 MARKS]

The following table gives the marks obtained by the students of a class in an exam out of 50.

$\begin{matrix} Marks & No. of Students B e l o w 10 & 5 B e l o w 20 & 10 B e l o w 30 & 23 B e l o w 40 & 31 B e l o w 50 & 40 \end{matrix}$

(i) Convert the cumulative frequency distribution into a regular frequency distribution.

(ii) Find the mean. [3 MARKS]

Calculate the median for the following distribution.

$\begin{matrix} M a r k s o b t a i n e d & N u m b e r o f s t u d e n t s B e l o w 10 & 6 B e l o w 20 & 15 B e l o w 30 & 29 B e l o w 40 & 41 B e l o w 50 & 60 B e l o w 60 & 70 \end{matrix}$ [4 MARKS]

Q. Question 10
The following table shows the cumulative frequency distribution of marks of 800 students in an examination.

\begin{matrix} M a r k s & N u m b e r o f s t u d e n t s B e l o w 10 & 10 B e l o w 20 & 50 B e l o w 30 & 130 B e l o w 40 & 270 B e l o w 50 & 440 B e l o w 60 & 570 B e l o w 70 & 670 B e l o w 80 & 740 B e l o w 90 & 780 B e l o w 100 & 800 \end{matrix}

Construct a frequency distribution table for the data above.

Join BYJU'S Learning Program

The following data gives the marks obtained by students in an exam. Class intervalFrequencyBelow 105Below 2010Below 3023Below 4031Below 5045Below 6049 (i)Convert the cumulative distribution to a regular distribution. (ii)Calculate the mode. [3 MARKS]

Table: 1 Mark Application: 2 Marks Class IntervalFrequency0−10510−20520−301330−40840−501450−604 Mode =I+(f1−f02f1−f0−f2)×h =20+13−526−5−8×10 =26.15

Table: 1 Mark
Application: 2 Marks

$\begin{matrix} Class Interval & Frequency 0 - 10 & 5 10 - 20 & 5 20 - 30 & 13 30 - 40 & 8 40 - 50 & 14 50 - 60 & 4 \end{matrix}$

Mode
$= I + (\frac{f_{1} - f_{0}}{2 f_{1} - f_{0} - f_{2}}) \times h$

$= 20 + \frac{13 - 5}{26 - 5 - 8} \times 10$

$= 26.15$