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Byju's Answer
Standard XII
Chemistry
Gibbs Free Energy & Spontaneity
The following...
Question
The following data is known about the melting of
K
C
l
:
Δ
H
=
7.25
k
J
m
o
l
−
1
;
Δ
S
=
+
0.007
K
J
K
−
1
m
o
l
−
1
Calculate its melting point.
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Solution
we have,
Δ
H
=
T
Δ
S
T
=
Δ
H
Δ
S
T
=
7250
7
K
T
=
1035
K
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0
Similar questions
Q.
The following data,
Δ
H
=
9.2
k
J
m
o
l
−
1
,
Δ
S
=
0.008
k
J
K
−
1
m
o
l
−
1
is known about the melting of a compound
A
B
. Its melting point is
Q.
Calculate
Δ
S
for following process.
X
(
s
)
at 100 K
⟶
X
(
l
)
at 200 K
Given : Melting point of
X
(
s
)
=
100
K
;
Δ
H
f
u
s
i
o
n
=
20
k
J
/
m
o
l
;
C
p
,
m
(
X
,
l
)
=
10
J
/
m
o
l
.
K
Q.
What will be the melting point of KCl if enthalpy change for the reaction is 7.25 J
m
o
l
−
1
and entropy change is 0.007 J
K
−
1
m
o
l
−
1
?
Q.
For the melting of
N
a
C
l
heat required is
7.26
k
c
a
l
m
o
l
−
1
and
Δ
S
increases by
6.73
c
a
l
m
o
l
−
1
K
−
1
. The melting point of the salt is:
Q.
Calculate the dissociation constant of
N
H
4
O
H
at 298 K, if
△
H
⊝
and
Δ
S
⊝
for the given changes are as follows:
N
H
3
+
H
⊕
⇌
⊕
N
H
4
;
Δ
H
⊝
=
−
52.2
k
J
m
o
l
−
1
,
Δ
S
⊝
=
1.67
J
K
−
1
m
o
l
−
1
H
2
O
⇌
H
⊕
+
⊝
O
H
;
Δ
H
⊝
=
56.6
k
J
m
o
l
−
1
;
Δ
S
⊝
=
−
76.53
J
K
−
1
m
o
l
−
1
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