Question

The following data shows the agricultural production in India during a certain year.

Foodgrain	Rice	Wheat	Coarse cereals	Pulses
Production (in millions of tonnes)	57	76	38	19

Draw a pie chart to represent the above data.

Answer 1

$$\begin{gathered} \mathrm{Total}\mathrm{production}=\left(57+76+38+19\right)=190 \\ \mathrm{Central}\mathrm{angle}\mathrm{of}\mathrm{each}\mathrm{foodgrain}=\left(\frac{\mathrm{production}\mathrm{of}\mathrm{each}\mathrm{foodgrain}}{\mathrm{total}\mathrm{production}}\times 360\right)° \\ \mathbf{Calculation}\mathbf{}\mathbf{of}\mathbf{}\mathbf{central}\mathbf{}\mathbf{angles} \end{gathered}$$

Food grain	production (in millions of tonnes)	Central angle
Rice	57	$108°$
Wheat	76	$144°$
Coarse cereals	38	$72°$
Pulses	19	$36°$

$$\begin{gathered} \mathbf{Construction}\mathbf{}\mathbf{of}\mathbf{}\mathbf{pie}\mathbf{}\mathbf{chart} \\ \mathrm{Steps}\mathrm{of}\mathrm{construction}: \\ 1.\mathrm{Draw}\mathrm{a}\mathrm{circle}\mathrm{of}\mathrm{any}\mathrm{convenient}\mathrm{radius}. \\ 2.\mathrm{Draw}\mathrm{a}\mathrm{horizontal}\mathrm{radius}\mathrm{of}\mathrm{the}\mathrm{circle}. \\ 3.\mathrm{Draw}\mathrm{sectors}\mathrm{whose}\mathrm{central}\mathrm{angles}\mathrm{are}108°,144°,72°\mathrm{and}36°. \\ 4.\mathrm{Shade}\mathrm{the}\mathrm{sectors}\mathrm{so}\mathrm{obtained}\mathrm{differently}\mathrm{and}\mathrm{label}\mathrm{each}\mathrm{one}\mathrm{of}\mathrm{them}. \\ \mathrm{Thus},\mathrm{we}\mathrm{obtain}\mathrm{the}\mathrm{required}\mathrm{pie}\mathrm{chart}\mathrm{as}\mathrm{shown}\mathrm{in}\mathrm{the}\mathrm{figure}\mathrm{below}. \end{gathered}$$