The following data was obtained during the first order thermal decomposition of SO 2 Cl 2 at a constant volume-SO 2 Cl 2 g - SO 2 g - Cl 2 g 180 - 0-4 11-hline2-100-0-7Nlhinelend array Calculate the rate constant-Given-log 4-0-602- log 3-0-477

In this case k=2.303/t logp_i/2p_i p_t =2.303/100 log0.4/(2×0.5) 0.7=2.303/100 log0.4/1 0.7 =2.303/100 log0.4/0 ...

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Le Chatelier's Principle for Del N Equals to 0

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Question

The following data was obtained during the first order thermal decomposition of $S O_{2} C l_{2}$ at a constant volume:
$S O_{2} C l_{2} (g) \to S O_{2} (g) + C l_{2} (g)$

$\begin{matrix} Experiment & Time / s^{- 1} & Total pressure/atm 1 & 0 & 0.4 2 & 100 & 0.7 \end{matrix}$

Calculate the rate constant.

(Given:log 4=0.602, log 3=0.477)

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The following data were obtained during the first order thermal decomposition of $S O_{2} C l_{2}$ at a constant volume.

$S O_{2} C l_{2} (g) \to S O_{2} (g) + C l_{2} (g)$

$\begin{matrix} E x p e r i m e n t & T i m e / s^{- 1} & T o t a l p r e s s u r e / a t m 1 & 0 & 0.5 2 & 100 & 0.6 \end{matrix}$

Calculate the rate of the reaction when total pressure is 0.65 atm.

S O_{2} C l_{2}

S O_{2} C l_{2} (g) \to S O_{2} (g) + C l_{2} (g)

0.65

S O_{2} {C l}_{2}

S O_{2} C l (g) ⟶ S O_{2} (g) + {C l}_{2} (g)

log 4 = 0.6021, log 2 = 0.3010

S O_{2} C l_{2}

S O_{2} C l_{2} (g) \to S O_{2} (g) + C l_{2} (g)

S O_{2} C l_{2}

S O_{2} C l_{2 (g)} \to S O_{2 (g)} + C l_{2 (g)}

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