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Question

The following data were obtained during the first order thermal decomposition of SO2Cl2 at a constant volume.

Experiment

Time/s−1

Total pressure/atm

1

0

0.5

2

100

0.6

Calculate the rate of the reaction when total pressure is 0.65 atm.

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Solution

The thermal decomposition of SO2Cl2 at a constant volume is represented by the following equation.

After time, t, total pressure,

Therefore,

= 2 P0 − Pt

For a first order reaction,

When t = 100 s,

= 2.231 × 10−3 s−1

When Pt = 0.65 atm,

P0 + p = 0.65

p = 0.65 − P0

= 0.65 − 0.5

= 0.15 atm

Therefore, when the total pressure is 0.65 atm, pressure of SOCl2 is

= P0 − p

= 0.5 − 0.15

= 0.35 atm

Therefore, the rate of equation, when total pressure is 0.65 atm, is given by,

Rate = k()

= (2.23 × 10−3 s−1) (0.35 atm)

= 7.8 × 10−4 atm s−1


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