Question

The following data were obtained for $H_{2}O$ and $H_{2}S$:

	Formula Mass	Freezing Point($o$C)	Boiling Point($o$C)
$H_{2}O$	$18$	$0$	$100$
$H_{2}S$	$34$	$-83$	$-60$

Which of the following will best describe the difference in physical properties among these two compound?

• A. The $H_{2}S$ has stronger bonds between molecules
• B. The $H_{2}O$ has a great deal of hydrogen bonding
• C. The bond angles differ by about ${15}^o$
• D. The formula mass is of prime importance
• E. The oxygen atom has a smaller radius and thus cannot bump into other molecules as often as the sulfur

Answer 1

The correct option is B The $H_{2}O$ has a great deal of hydrogen bonding

Due to presence of inter-molecular hydrogen bonding in water, several water molecule are associated. Large amount of energy is required to break this association.This results in high melting point and boiling point for water.