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Question
The following data were obtained for the reaction
NO(g)+Br2(g)→2NOBr(g)
Expt initial conc initial rate
Expt Initial conc Initial rate: [NO] [Br2] mol L−1 min−1 0.1 0.1 1.3×10−6 0.2 0.1 5.2×10−6 0.3 0.3 1.56×10−5
The order of the reaction is:
The following data were obtained for the reaction
NO(g)+Br2(g)→2NOBr(g)
Expt initial conc initial rate
| Expt | Initial conc | Initial rate: |
| [NO] | [Br2] | mol L−1 min−1 |
| 0.1 | 0.1 | 1.3×10−6 |
| 0.2 | 0.1 | 5.2×10−6 |
| 0.3 | 0.3 | 1.56×10−5 |
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Solution
The correct option is D 3
The expression for the rate of the reaction is r=k[NO]n[Br2]m−(1)
When the concentration of NO is doubled and the concentration of Br2 remains same, the rate expression becomes 4r=k[2NO]n[Br2]m−(2)
When the concentration of NO is doubled and the concentration of Br2 is tripled, the rate expression becomes 12r=k[2NO]n[3Br2]n−(3)
Divide equation (2) with equation (1) to obtain n=2
Divide equation (3) with equation (1) to obtain m=1
Hence, the order of the reaction is 2+1=3.
The expression for the rate of the reaction is r=k[NO]n[Br2]m−(1)
When the concentration of NO is doubled and the concentration of Br2 remains same, the rate expression becomes 4r=k[2NO]n[Br2]m−(2)
When the concentration of NO is doubled and the concentration of Br2 is tripled, the rate expression becomes 12r=k[2NO]n[3Br2]n−(3)
Divide equation (2) with equation (1) to obtain n=2
Divide equation (3) with equation (1) to obtain m=1
Hence, the order of the reaction is 2+1=3.
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