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Question

The following defines a relation on N:
R={x>y,x,yN}.
Determine whether it is reflexive, symmetric and transitive.

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Solution

The given relation R on the set of natural (N) number is not a reflexive as (x,x)R since xx for any xN.
Again the relation is not symmetric as (3,2)R but (2,3)R.
But the relation is transitive as if (x,y)R,(y,z)R(x,z)R for all x,y,zN. Since x>y,y>z gives x>z.

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