Question

The following diagram indicates the energy levels of a certain atom when the system moves from 2E level to E, a photon of wavelength $\lambda$ is emitted. The wavelength of photon produced during its transition from $\frac{4E}{3}$ level to E is

• A. $\frac{\lambda }{3}$
• B. $\frac{3\lambda }{4}$
• C. $\frac{4\lambda }{3}$
• D. $3\lambda$

Answer 1

The correct option is D $3\lambda$

$2E-E=\frac{hc}{\lambda }\Rightarrow E=\frac{hc}{\lambda }$
$\frac{4E}{3}-E=\frac{hc}{{\lambda }^{‘}}\Rightarrow =\frac{E}{3}=\frac{hc}{{\lambda }^{‘}}\therefore \frac{{\lambda }^{‘}}{\lambda }=3\Rightarrow {\lambda }^{‘}=3\lambda$