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Question

# The following diagram indicates the energy levels of a certain atom. When the system moves from 2E level to E, a photon of wavelength λ is emitted. The wavelength of photon emitted during its transition from 4E3 level to E level is:

A
λ3
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B
3λ4
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C
4λ3
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D
3λ
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Solution

## The correct option is D 3λWhen the system moves from 2E level to E level, then, ΔE=2E−E=hcλ ⇒E=hcλ ....(1) When the system moves from 43E level to E level, then, ΔE=43E−E=hcλ′ ⇒E3=hcλ′ ....(2) Dividing equation (1) by equation (2), we get, EE/3=hcλ×λ′hc ⇒3=λ′λ ⇒λ′=3λ Hence, option (D) is correct. Key Idea: ΔE=hcλ Where, λ is the wavelength of radiation and ΔE is the change in the energy from one state to another.

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