The following distribution shows the daily pocket allowance of children of a locality. The mean pocket allowance is Rs.18. Find the missing frequency 'f' using assumed mean method
Pocket allowanceNumber of children11−13713−15615−17917−191319−21f21−23523−254
Let the assumed mean 'a' be 18
ClassIntervalfixidi=xi−afidi11−13712−6−4213−15614−4−2415−17916−2−1817−191318=a0019−21f2022f21−2352242023−25424624
Here,
∑fi=44+f
∑fidi=2f−40
∵Mean=a+∑fidi∑fi
⇒18=18+2f−4044+f⇒2f−40=0⇒f=20
∴ The missing frequency is 20.