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Question

The following distribution shows the daily pocket allowance of children of a locality. The mean pocket allowance is Rs.18. Find the missing frequency 'f' using assumed mean method

Pocket allowanceNumber of children11−13713−15615−17917−191319−21f21−23523−254

A
80
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B
84
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C
20
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D
24
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Solution

The correct option is C 20

Let the assumed mean 'a' be 18

ClassIntervalfixidi=xiafidi11137126421315614424151791621817191318=a001921f2022f21235224202325424624

Here,

fi=44+f

fidi=2f40

Mean=a+fidifi

18=18+2f4044+f2f40=0f=20

The missing frequency is 20.


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