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Question

The following distribution shows the daily pocket allowance of children of a locality. The mean pocket allowance is Rs. 18. Find the missing frequency f.
Daily pocket allowance (in Rs.)
1113
1315
1517
1719
1921
2123
2325
Number of children
7
6
9
13
f
5
4

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Solution


Lets take assumed mean, A as 16
Class interval =2

ui=xiAh=xi162

Now, we have A=16,¯x=18 and h=2

We know that,
Mean, ¯x=A+h(1Nfiui)
18=16+2(2f+24f+44)

2f+24f+44=1

f+44=2f+24
f=20

Hence, the value of missing frequency, f=20

498343_465433_ans.png

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